Course-v1:Arbisoft+CS200+Eng/en/block-v1:Arbisoft+CS200+Eng+type@problem+block@3370b6c207a1473e8a55c982ccd5fb4d: Difference between revisions

{"@metadata": {"sourceLanguage": "en", "priorityLanguages": ["fr"], "allowOnlyPriorityLanguages": true}, "problem.p.1": "\n      Circuit schematic problems allow students to create virtual circuits by\n      arranging elements such as voltage sources, capacitors, resistors, and\n      MOSFETs on an interactive grid. The system evaluates a DC, AC, or\n      transient analysis of the circuit.\n  ", "problem.p.2": "\n      For more information, see\n      ", "problem.p.2.a": "\n      Circuit Schematic Builder Problem", "problem.p.2.i": "Building and Running an edX Course", "problem.p.3": "\n      When you add the problem, be sure to select ", "problem.p.3.strong.1": "Settings", "problem.p.3.strong.2": "Display Name", "problem.p.4": "You can use the following example problems as models.", "problem.schematicresponse.1.p": "Make a voltage divider that splits the provided voltage evenly.", "problem.schematicresponse.1.answer": "\ndc_value = \"dc analysis not found\"\nfor response in submission[0]:\n  if response[0] == 'dc':\n      for node in response[1:]:\n          dc_value = node['output']\n\nif dc_value == .5:\n  correct = ['correct']\nelse:\n  correct = ['incorrect']\n", "problem.schematicresponse.1.solution.div.p.1": "Explanation", "problem.schematicresponse.1.solution.div.p.2": "\n                  You can form a voltage divider that evenly divides the input\n                  voltage with two identically valued resistors, with the sampled\n                  voltage taken in between the two.\n              ", "problem.schematicresponse.2.p": "Make a high-pass filter.", "problem.schematicresponse.2.answer": "\nac_values = None\nfor response in submission[0]:\n  if response[0] == 'ac':\n      for node in response[1:]:\n          ac_values = node['NodeA']\nprint \"the ac analysis value:\", ac_values\nif ac_values == None:\n  correct = ['incorrect']\nelif ac_values[0][1] < ac_values[1][1]:\n  correct = ['correct']\nelse:\n  correct = ['incorrect']\n", "problem.schematicresponse.2.solution.div.p.1": "Explanation", "problem.schematicresponse.2.solution.div.p.2": "\n                  You can form a simple high-pass filter without any further\n                  constraints by simply putting a resistor in series with a\n                  capacitor. The actual values of the components do not really\n                  matter in this problem.\n              ", "display_name": "Circuit Schematic Builder"}